Respuesta :
Answer: (a)
Explanation:
Given
Mass of large truck is 4M with velocity V
Mass of small car is M which is at rest
After the collision car and truck stick together
Conserving momentum
[tex]\Rightarrow 4MV+M(0)=5M\times V_f\\\\\Rightarrow V_f=\dfrac{4}{5}V[/tex]
For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.
So, for elastic collision velocity [tex]V_f_2=\frac{4}{5}V[/tex]
As a result of collision when there is no loss in the kinetic energy of the object then the collision is said to be elastic and the kinetic energy and the momentum of the objects are conserved.
The momentum is written as:
[tex]\rm m_{1}v_{1}+m_{2}v_{2} = m_{1}v_{1}'+m_{2}v_{2}'[/tex]
Where, mass = m and velocity = v
The following option is true:
Option a. [tex]\dfrac{4}{5} \rm V[/tex]
The momentum can be estimated by:
Given,
- Mass of large truck = 4M
- Mass of small car = M
- The velocity of truck = V
After the collision the conserving momentum will be:
[tex]\begin{aligned}\rm 4MV + M(0) &= 5\rm M \times V_{f}\\\\\rm V_{\rm f} &= \dfrac{4\rm MV}{5\rm M}\\\\\rm V_{f} &= \dfrac{4}{5V}\end{aligned}[/tex]
There will be no acceleration as the momentum is conserved and the center of mass is the same.
Therefore, elastic collision will have a momentum of [tex]\dfrac{4}{5} \rm V[/tex].
To learn more about momentum and elastic collision follow the link:
https://brainly.com/question/8169285
