Two sides of a parallelogram are 8.5 feet and 3.8 feet. The measure of the angle
between these sides is 107º. Find the area of the parallelogram to the nearest 10th of
a square foot.

The area of a parallelogram is defined as the region or space covered by a parallelogram in a two-dimensional plane. A parallelogram is a special kind of quadrilateral. If a quadrilateral has two pairs of parallel opposite sides, then it is called a parallelogram.

Let the sides of a parallelogram a, b and height h.

Now the area of parallelogram= a*h

given data are

angle between two sides =107°

and sides are a=8.5 feet and b=3.8 feet

The height of the parallelogram [tex]h= bsin\alpha[/tex]

now height [tex]h= 3.8*sin107\\h=3.634 feet[/tex]

Now the area of parallelogram = 8.5*3.634

Now the area of parallelogram=30.9 ft²

To know more about it click on given link

https://brainly.com/question/23318204

#SPJ2

Two sides of a parallelogram are 8.5 feet and 3.8 feet. The measure of the angle between these sides is 107º. Find the area of the parallelogram to the nearest 10th of a square foot.

Respuesta :

Answer:

Step-by-step explanation:

Definition of parallelogram and its area

Otras preguntas

Two sides of a parallelogram are 8.5 feet and 3.8 feet. The measure of the angle
between these sides is 107º. Find the area of the parallelogram to the nearest 10th of
a square foot.