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Question 1: The sum of two consecutive multiples of 5 is 55. Find these multiples. Question 2: The present age of Sahil's mother is three times the present age of Sahil. After5 years their ages will add to 66 years. Find the present ages. Question 3: The perimeter of a rectangle is 13 cm and its width is 2- cm. Find its length.

Respuesta :

Answer:

1] Two consecutive multiples = 50,55. 2] Sahil , Mother current age = 13,42 3] Length of rectangle = 4.5  

Step-by-step explanation:

1] Let one multiple of 5 be = n. As there are two consecutive multiples, other multiple = n + 1. Given : sum of two consecutive multiples of 5 is 55

So, 5n + 5(n+1) = 55

5n + 5n + 5 = 55 ; 10n + 5 = 55 ; 10n = 50 - 5 = 50 ; n = 50 / 10 ; n = 5

n  {One multiple} = 5 ; Other multiple {n+1} = 5 + 1 = 6

2] Let present age of Sahil be = x. So, present age of Sahil mother = 3x

5 years hence : (x+5) + (3x+5) = 66  {Equation 1}

Solving Eq 1} : x + 5 + 3x + 5 = 66 ; 4x + 10 = 66 ; 4x = 66 - 10 ; 4x = 56

x = 56/4 ; x = 14 {Sahil Current Age}. Mother current age = 3x = 3 x 14 = 42

3] Perimeter of rectangle = 2 (Length + Width). Perimeter = 13 , Width = 2.

So, 13 = 2 (L +2) ; 13 = 2L + 4 ; 2L = 13 - 4 = 9 ; L = 9/2 ; Length = 4.5

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