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The chart shows the masses of selected particles.
Particle
Mass
2350
137 9 u
6
92
138
Ba
K:
on
94.9u
1.0 u
In the equation u + Ön – 133Ba + K+ + 36n+E , the energy E is equivalent to a mass of

1.
0.2 u
2.
2.0 u
3.
2.2 u
4.
0.0 u

The chart shows the masses of selected particles Particle Mass 2350 137 9 u 6 92 138 Ba K on 949u 10 u In the equation u Ön 133Ba K 36nE the energy E is equival class=

Respuesta :

Answer: 0.2 u

Explanation:

The atomic mass of nuclide is written as a superscript. On the left (reactants) aide of the nuclear equation shown, the total atomic mass is 235.0 + 1.0 u = 236 u. On the right (products) side reaction, the total atomic mass is 137.9u + 94.9u + 3 x 1.0u = 235.8 u. Therefore, 0.2 mass units must have been converted into energy.