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Miss fernandez built two rectangular gardens the length of garden a is 2 feet longer than twice its width the list of garden b is 1 foot less than the width of garden a the length of garden b is 2.5 times its width the two gardens have the same perimeter what are the dimensions of the gardens

Respuesta :

wizard123
For garden A, let width = w, length = L
For garden B, let width = x, length = y

So we are given the following:
L = 2+2w
x = w - 1
y = 2.5x
2w+2L = 2x+2y   ------> w+L = x+y

Ok lets do some substituting into the perimeter equation
[tex]w + (2+2w) = (w-1) + 2.5(w-1)[/tex]
adding like terms...
0.5w = 5.5
w = 11

This means that:
L = 2+2(11) = 24

x = 11-1 = 10
y = 2.5x = 2.5(10) = 25

Final solution:
Garden A is 11 by 24
Garden B is 10 by 25