The sum of interior angle of the given regular hexagon is 720 degree. The area of the hexagon with side of 8 units is 96√3 square units
Area of a hexagon
The sum of interior angle of the given regular hexagon is 720 degrees
The measure of one of the angles is 120 degrees
<ABO = 120/2 = 60 degrees
Since all the angles of triangle ABO are the same, hence AB = 8 units
Determine the area of the hexagon
A = 3√3/2 a²
Substitute a = 8 units
A = 3√3/2 (8)²
A = 3√3/2 * 64
A = 3√3 * 32
A = 96√3 square units
Hence the area of the hexagon with side of 8 units is 96√3 square units
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