Answer: (0, 1)
Step-by-step explanation:
For starters, the two equations are the same line if you put the first one into y=mx+b form you'll see that they are, so basically any solution to one is the same for the other.
I choose subsitution to find the solution set
[tex]3x = 3y -3\\y = x + 1 \\3x = 3(x+1) -3 \\3x = 3x + 3 -3 \\3x - 3x= 3-3 \\x = 0 \\\\y = x+ 1\\y = 0 +1 \\y = 1[/tex]
This method is the easiest given that the problem already tells you what y is equal to. So this way you can substitute this in for y in the first equation and find x and then from there find y in the second.