The Hershey Company has been receiving complaints that their chocolate almond bars contain fewer almonds than they've previously contained. Hershey's records show that over time each bar of candy contains a mean of 17 almonds. A sample of 30 of last month's chocolate bars has a mean of 14 almonds with a standard deviation of 8. Test the hypothesis (alpha

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State appropriate Hypothesis for performing a significance test. Be sure to define the parameter of interest. (u = mu)

[tex]H_{null}:u=17 \\H_{a}:u<17[/tex]        Where mu = the true mean of almonds in each bar of candy.

Calculate the test statistic and the P-Value.

mu = 17

x-bar = 14

[tex]S_{x} = 8[/tex]

[tex]n = 30[/tex]

Use the T-Test (STAT) if you have a Graphing Calculator.

Interpret the P-Value in context.

Assuming the mean number of almonds in each candy bar is 17, there is a [P-Value] probability of getting a sample mean of 14 by chance alone.

What is the decision at the given significance level?

P-val of [P-Value] is (> or <?) to the alpha level [[tex]a[/tex]], so you must (fail to reject or reject?) the Null Hypothesis.

What do you conclude? (If P-val is smaller than the alpha level, reject the null hypothesis, meaning there is significant evidence.)

Because the P-Value of [P-Value] is (less/greater) than [tex]a = (?)[/tex], the observed result (is or is not?) statistically significant. There (is or is not?) significant evidence to conclude that the chocolate almond bars contain fewer almonds than they've previously contained.