Answer:
Final temperature = [tex]43.53^{\circ} C[/tex]
Explanation:
Given that,
Heat added, Q = 250 J
Mass, m = 30 g
Initial temperature, T₁ = 22°C
The Specific heat of Cu= 0.387 J/g °C
We know that, heat added due to the change in temperature is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1[/tex]
Put all the values,
[tex]T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C[/tex]
So, the final temperature is equal to [tex]43.53^{\circ} C[/tex].
