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A train is travelling at a speed
of 90 km h-¹. Brakes are applied
so as to produce a uniform
acceleration of - 0.5 m s-². Find
how far the train will go before it
is brought to rest.​

Respuesta :

Explanation:

[tex]speed : [/tex]

[tex]speed : U = \frac{(90 \times 1000) \: m}{(1 \times 3600) \: s} \\ = 25 \: m {s}^{ - 1} \\ from \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {25}^{2} \times (2 \times - 0.5 \times S) \\ 625 = S \\ S = 625 \: m[/tex]

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