Respuesta :
Same idea here as last time.
You have a y-value, substitute it in the problem.
y=x+12
4x+2y=27
4x+2(x+12)=27
4x+2x+24=27
6x+24=27
-24 -24
6x=3
/6
x=.5
plug back in
y=(.5)+12
y=12.5
final answer:
x=.5,y=12.5
You have a y-value, substitute it in the problem.
y=x+12
4x+2y=27
4x+2(x+12)=27
4x+2x+24=27
6x+24=27
-24 -24
6x=3
/6
x=.5
plug back in
y=(.5)+12
y=12.5
final answer:
x=.5,y=12.5