Answer:
[tex]m_{H2SO4[/tex] = 61.25 g
[tex]m_{Na2SO4}[/tex] = 88.75 g
Explanation:
[tex]m_{NaOH}[/tex] = [tex]\frac{200 . 25 }{100}[/tex] = 50 g
⇒ [tex]n_{NaOH}[/tex] = [tex]\frac{50}{40}[/tex] = 1.25 (moles)
2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O
2 : 1 : 1 : 2
1.25 (moles)
⇒ [tex]n_{H2SO4}[/tex] = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒ [tex]m_{H2SO4}[/tex] = 0.625 × 98 = 61.25 g
[tex]n_{Na2SO4}[/tex] = 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒[tex]m_{Na2SO4}[/tex] = 0.625 × 142 = 88.75 g
