Answer:
1.00 × 10³ g
Explanation:
Step 1: Given data
Step 2: Calculate the moles of ethanol vaporized
Vaporization is the passage of a substance from liquid to gas. We can calculate the number of moles (n) vaporized using the following expression.
Q = ΔH°vap × n
n = Q / ΔH°vap
n = 843.2 kJ / (38.6 kJ/mol) = 21.8 mol
Step 3: Calculate the mass corresponding to 21.8 moles of ethanol
The molar mass of ethanol is 46.07 g/mol.
21.8 mol × 46.07 g/mol = 1.00 × 10³ g
The conversion of the liquid into water vapor is called vaporization.
The correct answer to the question is [tex]1.00 * 10^3 g[/tex]
The data given in the question is as follows:-
The formula we will use to calculate the moles is as:-
[tex]Q = H^ovap* n\\n = \frac{Q}{H^ovap}\\n = \frac{843.2 kJ}{(38.6 kJ/mol)} \\\\= 21.8 mol[/tex]
To calculate the mass of the following is as follows:-
[tex]21.8 mol* 46.07 g/mol = 1.00 * 10^3 g[/tex]
Hence the correct answer is [tex]1.00 * 10^3 g[/tex].
For more information, refer to the link:-
https://brainly.com/question/22810476
