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What is the slope of the line through (–5,2) and (6,7) in the standard (x,y) coordinate plane?

9
9

5
5

-5
-5

5
11
5 over 11

−
5
11

Respuesta :

Step-by-step explanation:

[tex]slope = \frac{\triangle \: y}{\triangle \: x} \\ = \frac{(7 - 2)}{(6 - ( - 5))} \\ = \frac{5}{11} \\ slope = (5 ,11)[/tex]

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