Answer:
the number of possibilities that can be drace himself up for the day is 216
Step-by-step explanation:
Given that
jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes
We need to find out the possibilities that can be drace himself up for the day
So here
[tex]= 12C_1 \times 6C_1 \times 3C_1\\\\= \frac{12!}{1!(12 - 1)!} \times \frac{6!}{1!(6 - 1)!} \times \frac{3!}{1!(3 - 1)!}\\\\= \frac{12!}{1!(11)!} \times \frac{6!}{1!(5)!} \times \frac{3!}{1!(2)!}\\\\= 12 \times 6 \times 3\\\\= 216[/tex]
Hence, the number of possibilities that can be drace himself up for the day is 216
The same would be considered and relevant too
