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The diagram shows a rectangle with length
2)
(3d + 2) am and width (d+5) cm.
3d+2
d+5
a Write an expression for the perimeter of the
rectangle.
b Given that the perimeter is 30 cm, make and
solve an equation to find a
c Find the area of this rectangle
M

The diagram shows a rectangle with length 2 3d 2 am and width d5 cm 3d2 d5 a Write an expression for the perimeter of the rectangle b Given that the perimeter i class=

Respuesta :

Step-by-step explanation:

Given that,

Length, l = (3d+2) m

Width, b = (d+5) m

(a) Perimeter of the rectangle,

P = 2(l+b)

P = 2(3d+2+d+5)

= 2(4d+7)

P = 8d+14

(b) If P = 30 cm.

8d+14 = 30

8d = 16

d = 2

(c) l = (3(2)+2) = 8 m

b = (2+5) = 7 m

The area of this rectangle,

A = lb

A = 8×7

A = 56 cm²

Hence, this is the required solution.

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