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asuwafohjames

Answer:

8.22 g/dm³

Explanation:

Applying,

PV = nRT............... Equation 1

Where P = pressure of krypton, V = Volume of krypton, n = number of moles, R = molar gas constant, T = Temperature

But,

number of mole (n) = mass(m)/molar mass(m')

n = m/m'.............. Equation 2

Substitute equation 2 into equation 1

PV = mRT/m'

P = (m/V)(RT)/m'................ Equation 3

Also,

Density (D) = Mass(m)/Volume(V)

D = m/V.............. Equation 4

Substitute equation 4 into equation 3

P = DRT/m'

D = Pm'/RT.................... Equation 5

From the question,

Given: P = 3.00 atm, T = 100°C = (273+100) = 373 K, m' = 83.8 g/mol

Constant: R = 0.082atm.dm³.K⁻¹.mol⁻¹

Substitute these values into equation 5

D = (3×83.8)/(0.082×373)

D = 251.4/30.586

D = 8.22 g/dm³

mahima6824soni

 The density of krypton gas is 8.22 g/dm³

What is density?

Density of any substance is its mass per unit volume.

By ideal gas law

PV = nRT

Where p = pressure is 3.00 atm,

t = temperature is 100 °C = 273 + 100 = 373 K

Molar mass = 83.8 g/mol

R = constant is 0.082 atm.

[tex]\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}[/tex]

Substituting the equation in 1

P = (m/V)(RT)/m'

Now, density = m/V

Then,

[tex]\rm D = \dfrac{Pm'}{RT}[/tex]

[tex]\rm D = \dfrac{3\times 83.8}{0.082\times373} = 8.22 g/dm^3\\[/tex]

Thus, the density is 8.22 g/dm3.

Learn more about density, here

https://brainly.com/question/952755

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