Answer:
A. 4 m³
B. 1 m³
Explanation:
A. Determination of the new volume.
Initial Volume (V₁) = 2 m³
Initial temperature (T₁) = 27 °C + 273 = 300 K
Final temperature (T₂) = 327 °C + 273 = 600 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
2 / 300 = V₂ / 600
Cross multiply
300 × V₂ = 2 × 600
300 × V₂ = 1200
Divide both side by 300
V₂ = 1200 / 300
V₂ = 4 m³
B. Determination of the new volume.
Initial Volume (V₁) = 2 m³
Initial temperature (T₁) = 27 °C + 273 = 300 K
Final temperature (T₂) = –123 °C + 273 = 150 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
2 / 300 = V₂ / 150
Cross multiply
300 × V₂ = 2 × 150
300 × V₂ = 300
Divide both side by 300
V₂ = 300 / 300
V₂ = 1 m³
