Answer:
The time will be "3 years".
Step-by-step explanation:
The given values are:
Principle,
P = 5120
Amount,
A = 7290
Rate,
r = 12.5
Time,
n = ?
As we know,
⇒ [tex]A = P[1+\frac{r}{100} ]n[/tex]
On substituting the values, we get
⇒ [tex]7290=5120[1+\frac{12.5}{100} ]n[/tex]
On applying cross-multiplication, we get
⇒ [tex]\frac{7290}{5120}=[1+\frac{125}{100}\times 100 ]n[/tex]
⇒ [tex]\frac{9}{8}\times 3=[8+\frac{1}{8} ]n[/tex]
⇒ [tex]n = 3 \ years[/tex]
