Answer: Yes, [tex]15\ m^2[/tex]
Step-by-step explanation:
Given
The surface area of the house [tex]A=500\ m^2[/tex]
Ayden aims to finish 80% of the painting
The actual painting done by him is [tex]A_c=415\ m^2[/tex]
Now 80% of the total is
[tex]\Rightarrow A'=500\times \dfrac{80}{100}=400\ m^2[/tex]
Clearly, actual painting done is more than 80% of the painting
[tex]\therefore[/tex] Ayden meet his goal
[tex]\Rightarrow A_c-A'=415-400=15\ m^2[/tex]
He painted [tex]15\ m^2[/tex] more than his target
