Given:
The inequality is:
[tex]2\times 6<5(3-x)[/tex]
To find:
The solution of the given inequality.
Solution:
We have,
[tex]2\times 6<5(3-x)[/tex]
It can be written as
[tex]12<15-5x[/tex]
[tex]12-15<-5x[/tex]
[tex]-3<-5x[/tex]
Divide both sides by 5 and change the sign of inequality.
[tex]\dfrac{-3}{-5}>x[/tex]
[tex]0.6>x[/tex]
It means all the values that are greater than 0.6 are in the solution set.
Since the value 0.6 is not included in the solution, therefore there is an open circle at 0.6.
The solution set of the given inequality on the number line is shown below:
