[tex]\huge\mathfrak\blue{answer}[/tex]
[tex]c) \: 23\%[/tex]
Let's figure out how many pieces of candy there is in total:
10 + 12 + 6 = 28
In total, there are 28 pieces of candy.
Let's find the probability that a piece is sour:
[tex] \frac{10}{28} = \frac{5}{14} [/tex]
The probability of pulling a sour piece out of the bag is 5/14.
This means that the probability that the candy pulled is not sour is 9/15 (or simplified 3/5)
To find the probability that the first candy picked out is sour AND the second candy picked is not sour we have to multiply the probabilities of both:
[tex] \frac{5}{14} * \frac{3}{5} = 0.229 = 23\%[/tex]
[tex]\huge\sf\blue{thank \: you}[/tex]
(Brainliest would be appreciated :))
