Answer:
Step-by-step explanation:
[tex]\frac{12x}{2x-3x-10}-\frac{x}{x-5}=\frac{12x}{-x-10}-\frac{x}{x-5}\\\\=\frac{12x}{-(x+10)}-\frac{x}{x-5}\\\\=\frac{-12x}{x+10}-\frac{x}{x-5}\\\\=\frac{-12x*(x-5)}{(x+10)*(x-5)}-\frac{x*(x+10)}{(x-5(x+10)}\\\\=\frac{-12x*x-5*(-12x)}{(x+10)(x-5)}-\frac{x*x+x*10}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x}{(x+10)(x-5)}-\frac{x^{2}+10x}{(x-5)(x+10)}\\\\=\frac{-12x^{2}+60x-(x^{2}+10x)}{(x+10)(x-5)}\\\\=\frac{-12x^{2} + 60x - x^{2}-10x}{x^{2}+5x-50}\\\\=\frac{-13x^{2}+50x}{x^{2}+5x-50}[/tex]
