Answer:
2nd option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- [tex]\frac{3}{2}[/tex], 0) and (x₂, y₂ ) = (0, [tex]\frac{3}{4}[/tex] )
m = [tex]\frac{\frac{3}{4}-0 }{0+\frac{3}{2} }[/tex] = [tex]\frac{\frac{3}{4} }{\frac{3}{2} }[/tex] = [tex]\frac{1}{2}[/tex] and c = [tex]\frac{3}{4}[/tex] , then
y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{3}{4}[/tex] ( multiply through by 4 to clear the fractions )
4y = 2x + 3 ( subtract 4y from both sides )
0 = 2x - 4y + 3 , that is
2x - 4y + 3 = 0 ← equation of line
