Answer:
It takes 6.52 s to complete the 150 m track.
Explanation:
Let's find the position of the cyclist during the acceleration.
[tex]x_{1}=v_{0}t+0.5at^{2}[/tex]
[tex]x_{1}=0.5(3.8)(4.5)^{2}[/tex]
[tex]x_{1}=38.48\: m[/tex]
Now, the final speed at this distance will be:
[tex]v_{f}=v_{0}+at[/tex]
[tex]v_{f}=3.8*4.5[/tex]
[tex]v_{f}=17.1\: m/s[/tex]
Now, we know that x(tot) = 150 m, the remaining part will be:
[tex]x_{2}=150-38.48=111.5\: m[/tex]
Therefore, the time is:
[tex]t=\frac{x_{2}}{V_{f}}[/tex]
[tex]t=\frac{111.5}{17.1}[/tex]
[tex]t=6.52\: s[/tex]
I hope it helps you!
