A spring is 17.5 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 27.5 N, causing the spring to stretch to a length of 19.3 cm.
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What is the force constant of this spring?
Express your answer in newtons per meter.
The Spring equation is k*x where k is the spring constant and x is the change in distance in meters. So you set 27.5=K*.018, (.018 comes from .193-.175). You then divide 27.5 by .018 to get the spring constant
