Respuesta :
Answer:
Option B will be your answer
Step-by-step explanation:
[tex] \sin(60) = \frac{h}{30} [/tex]
[tex] \frac{ \sqrt{3} }{2} = \frac{h}{ \frac{3}{15} } [/tex]
[tex]h = 15 \sqrt{3} ft[/tex]
hope it helps you...
Answer:
Option B will be your answer
Step-by-step explanation:
[tex] \sin(60) = \frac{h}{30} [/tex]
[tex] \frac{ \sqrt{3} }{2} = \frac{h}{ \frac{3}{15} } [/tex]
[tex]h = 15 \sqrt{3} ft[/tex]
hope it helps you...