Answer:
Δt = 5.85 s
Explanation:
For this exercise let's use Faraday's Law
emf = [tex]- \frac{d \phi}{dt}[/tex] - d fi / dt
[tex]\phi[/tex] = B. A
\phi = B A cos θ
The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.
suppose a linear change of the magnetic field
emf = - A [tex]\frac{B_f - B_o}{ \Delta t}[/tex]
Dt = - A [tex]\frac{B_f - B_o}{emf}[/tex]
the final field before a fault is zero
let's calculate
Δt = - 0.046 (0- 1.4) / 0.011
Δt = 5.85 s
