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I have an unknown initial volume of gas
held at a temperature of 115 K in a
container with a pressure of 6 atm. I
increase the temperature to 225 K and
decrease the pressure to 2,800 mmHg
and it causes the final volume of the gas
to be 29 L. What was the initial
volume?

Respuesta :

drpelezo

Answer:

V₁ = 0.025 Liters = 25 ml

Explanation:

P₁ = 6 Atm      P₂ = 7800mm/760mm/Atm = 0.01 Atm

V₁ = ?              V₂ = 29 Liters

T₁ = 115 K        T₂ = 225 K

P₁V₁/T₁ = P₂V₂/T₂ => V₁ = P₂V₂T₁/P₁T₂

V₁ = (0.01 Atm)(29L)(115K)/(6 Atm)(225K) = 0.025 Liters = 25ml

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