Answer:
2.[tex]-2m^4-6m^2+4m+9[/tex]
3.[tex]-2m^4-6m^2-4m+9[/tex]
Step-by-step explanation:
In general we can write a polynomial in standard form as
[tex]ax^n+bx^n^-^1+cx^n^-^2+...+px+q[/tex]
Given [tex]4m-2m^4-6m^2-4m+9[/tex]
Combine the like terms: 4m and -4m
4m-4m=0
We have 4m-4m=0
So, write the remaining terms
[tex]-2m^4-6m^2+9+0[/tex]
= [tex]-2m^4-6m^2+9[/tex]
This is in decreasing order of powers.
Hence the answer is the standard form is
[tex]-2m^3-6m^2+9[/tex]
But in the given options, you can choose option 2 and option 3 are in standard form.
Because they are in decreasing order of powers.
In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.
-2m^4-6m^2+4m+9
-2m^4-6m^2-4m+9
I hope this helps you.
And please comment if I need to do corrections.
Please let me know if you have any questions.
