Bobby put 1/3 of his lawn mowing money into his savings and uses the remaining 2/5 to buy a video game. If he has $12 left, how much did he have at first?

Respuesta :

Given:

Bobby put 1/3 of his lawn mowing money into his savings

He uses the remaining 2/5 to buy a video game.

He has $12 left.

To find:

The amount did he have at first.

Solution:

Let x be the initial amount.

Bobby put 1/3 of his lawn mowing money into his savings. So, the remaining amount is

[tex]x-\dfrac{1}{3}x=\dfrac{2}{3}x[/tex]

He uses the remaining 2/5 to buy a video game. Then the remaining amount is

[tex]Remaining=\dfrac{2}{3}x-\dfrac{2}{3}x\times \dfrac{2}{5}[/tex]

[tex]Remaining=\dfrac{2}{3}x-\dfrac{4}{15}x[/tex]

[tex]Remaining=\dfrac{10x-4x}{15}[/tex]

[tex]Remaining=\dfrac{6x}{15}[/tex]

[tex]Remaining=\dfrac{2x}{5}[/tex]

It is given that the remaining amount is $12.

[tex]12=\dfrac{2x}{5}[/tex]

[tex]12\times 5=2x[/tex]

[tex]60=2x[/tex]

Divide both sides by 2.

[tex]\dfrac{60}{2}=x[/tex]

[tex]30=x[/tex]

Therefore, Bobby have $30 at first.