Answer:
[tex]n=1.732mol[/tex]
[tex]\% N=18.7\%[/tex]
Explanation:
Hello!
In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:
[tex]n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol[/tex]
Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:
[tex]\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%[/tex]
Best regards!
