Answer:
The height of the hill is 0.46 m.
Explanation:
Given;
mass of the child and sled, m = 50 kg
initial velocity of the sled, u = 0
final velocity of the sled, v = 3 m/s
The height of the high is calculated from the law of conservation of energy;
P.E at top = K.E at bottom
mgh = ¹/₂mv²
gh = ¹/₂v²
[tex]h = \frac{v^2}{2g} \\\\h = \frac{3^2}{2\times 9.8} \\\\h = 0.46 \ m[/tex]
Therefore, the height of the hill is 0.46 m.
