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A polynomial function has a root of 6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2
and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which
statement about the graph is true?
The graph of the function is positive on (-6, -2).
The graph of the function is negative on (-00, 0).
The graph of the function is positive on (-2, 4).
The graph of the function is negative on (4,00).

Respuesta :

jcherry99

Answer:

Step-by-step explanation:

This graph is a monster. No one should solve it by hand. Desmos drew the one below. The way the graph looks, I would say it is negative at (4,0)

The first choice isn't a point on the graph.

(0,0) goes both ways.

(-2,4) is positive.

Ver imagen jcherry99

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