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Estimate the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.8 m and is released with a speed of 13 m/s

Respuesta :

Answer:

The force is 211.19 N.

Explanation:

Given that,

Mass = 7.0 kg

Distance = 2.8 m

Speed = 13 m/s

We need to calculate the acceleration

Using equation of motion

[tex]v^2=u^2+2as[/tex]

Put the value in the equation

[tex]13^2=0+2\times a\times2.8[/tex]

[tex]a=\dfrac{13^2}{2\times2.8}[/tex]

[tex]a=30.17\ m/s^2[/tex]

We need to calculate the force

Using newton's second law

[tex]F = ma[/tex]

Put the value into the formula

[tex]F = 7.0\times30.17[/tex]

[tex]F = 211.19\ N[/tex]

Hence, The force is 211.19 N.

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