Jeremiah makes 25% of the three-point shots he attempts. For a warm up, Jeremiah likes to shoot three-point shots until he successfully makes one. Let M be the number of shots it takes Jeremiah to successfully make his first three-point shot. Assume that the results of each shot are independent. Find the probability that Jeremiah's first successful shot occurs on his 3rd attempt. You may round your answer to the nearest hundredth. P(M=3)=

Respuesta :

Answer: .14

Step-by-step explanation: Khan Academy

Answer:

0.14

Step-by-step explanation:

First off, please read clearly.

This problem is asking for the probability that (M = 3).

The correct answer for this P(M = 3) problem is 0.14 through Khan Academy.

Even when you solve it, it is 0.14. The equation would be zero point twenty-five multiplied by parenthesis one minus zero point twenty-five closed parenthesis to the power of two. Written out the equation would be the following:

0.25x(1-0.25)^2

*** DO NOT MIX THIS UP WITH A VERY SIMILAR PROBLEM TO THIS. ***

There is a problem using this same Jeremiah situation but it asks for P(M < 4).

If you want the answer for P(M < 4) it is 0.58 so

P(M < 4) = 0.58

And another Jeremiah problem that asks for P(M > 6).

If you want the answer for P(M > 6) it is 0.18 so

P(M > 6) = 0.18

Have a nice day :)