bcarrera0005
bcarrera0005 bcarrera0005
  • 04-02-2021
  • Mathematics
contestada

how do I solve this?​

how do I solve this class=

Respuesta :

jimrgrant1 jimrgrant1
  • 04-02-2021

Answer:

sinJ = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

sinJ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{IK}{JK}[/tex] = [tex]\frac{12}{13}[/tex]

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