The dimensions of a rectangular piece of construction paper are 11.5 inches and 18 inches. Maggie folded the piece of paper along its diagonal.

Which measurement is closest to the length of the diagonal in inches?


7.6 in

13.8 in.

21.4 in

29.5 in.​

Respuesta :

C

Use the formula of the Pythagorean theorem. a^2 + b^2 = c^2

a = 11.5
b = 18

11.5^2 + 18^2 = 456.25^2
Sqrt(456.25) to find c

c=21.36 in.

The dimensions of a rectangular piece of construction paper are 11.5 inches and 18 inches. Therefore, the length of the diagonal in inches is 21.36.

What is Pythagoras' Theorem?

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

The dimensions of a rectangular piece of construction paper are 11.5 inches and 18 inches.

Maggie folded the piece of paper along its diagonal.

Use the formula of the Pythagorean theorem.

[tex]a^2 + b^2 = c^2[/tex]

We have

a = 11.5

b = 18

[tex]= 11.5^2 + 18^2\\ \\= 456.25^2[/tex]

[tex]c = \sqrt{(456.25)}\\\\c = 21.36[/tex]

Hence, the length of the diagonal in inches is 21.36.

Learn more about Pythagoras' theorem here:

https://brainly.com/question/12105522

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