Answer:
The area of the doghouse is [tex]59.5\ ft^{2}[/tex]
Step-by-step explanation:
we know that
The area of trapezoid is equal to
[tex]A=\frac{1}{2}(b1+b2)h[/tex]
where
b1,b2 are the parallel bases of trapezoid
h is the height of trapezoid
in this problem we have
[tex]b1=7\ ft[/tex]
[tex]b2=7+3=10\ ft[/tex]
[tex]h=7\ ft[/tex]
substitute
[tex]A=\frac{1}{2}(7+10)7=59.5\ ft^{2}[/tex]
