Answer:
c) ([tex](6-\sqrt{12} )(6+\sqrt{12} ) = 24[/tex]
d) ([tex](3+\sqrt{8} )(3-\sqrt{8} ) = 1[/tex]
Step-by-step explanation:
Step(i):-
Given that the binomial expression
([tex](6-\sqrt{12} )(6+\sqrt{12} )[/tex]
Multiply
( 36 + 6√12 -6√12 -(√12)²)
= ( 36 -12)
= 24
c) ([tex](6-\sqrt{12} )(6+\sqrt{12} ) = 24[/tex]
Step(ii):-
Given that the binomial expression
([tex](3+\sqrt{8} )(3-\sqrt{8} )[/tex]
Multiply
= 9 - 3√8 + 3√8 -(√8)²
= 9 - 8
= 1
d) ([tex](3+\sqrt{8} )(3-\sqrt{8} ) = 1[/tex]
