samk33334
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y = –x + 4
x + 2y = –8
How many solutions does this linear system have
one solution: (8, 0)
one solution: (0, 8)
no solution
infinite number of solutions

Respuesta :

texaschic101
y = -x + 4.....so sub in -x + 4 in for y in the other equation

x + 2y = -8
x + 2(-x + 4) = -8
x - 2x + 8 = -8
x - 2x = -8 - 8
-x = -16
x = 16

y = -x + 4
y = -16 + 4
y = - 12

one solution (16,-12)
johanrusli

If y = -x + 4 and x + 2y = - 8 , then for this linear system , it has only one solution : ( 16 , - 12 )

Further explanation

Simultaneous Linear Equations could be solved by using several methods such as :

  • Elimination Method
  • Substitution Method
  • Graph Method

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

We have two linear equations :

y = -x + 4

x + 2y = -8

We could rearrange the equations above become :

x + y = 4

x + 2y = -8

If we would like to use the Elimination Method , then two equations above could be subtracted.

( x + y ) - ( x + 2y ) = 4 - ( -8 )

-y = 12

y = -12

At last , we could find the value of x by substituting this y value into one of the two equations above :

x + y = 4

x - 12 = 4

x = 4 + 12

x = 16

For this linear system , it has only one solution : ( 16 , - 12 )

Learn more

  • Perimeter of Rectangle : https://brainly.com/question/12826246
  • Elimination Method : https://brainly.com/question/11233927
  • Sum of The Ages : https://brainly.com/question/11240586

Answer details

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

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