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The essential oil found in cloves, eugenol, can be isolated by steam distillation because it is insoluble in water and has a measurable vapor pressure at 100 â°c even though it has a much higher boiling point than water. use data from the table to calculate the volume of eugenol in 30 ml of distillate.

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We know that:
Molar Mass H2O: 18 g/mol 
Molar Mass of Eugenol: 164 g/mol 
Boiling point of H2O: 100 degrees C 
Boiling point of Eugenol: 254 degrees C 
Density of water: 1.0 g/mL 
Density of Eugenol: 1.05 g/mL 

Using formula:
V= [mole fraction x molar mass] / density 

mH20: 0.9947 * 18
          = 17.9046 / 1 g/mL
          = 17.9046 
morg: 0.0053 * 164  
        = 0.8692/ 1.05 g/mL
        = 0.8278 

V% = Vorg/(Vorg + VH2O) * 100 
(0.8278/18.7324) * 100 = 4.419% 

Yotal volume = 30 mL; therefore, 
0.0442 = (volume eugenol/30) 

(m eug/mH2O) = (peug*164/pH2O*18) 
(m eug/30) = (4*164/760*18) 
m eug = about 1.44g and 

volume = mass/density
            = 1.44/1.05
            = about 1.37 mL 
mahima6824soni

The volume of eugenol in 30 ml of distillate is 1.37 ml.

What is volume?

Volume is the space of that object that it occupied.

The molar mass of water is 18 g/mol

Molar mass of Eugenol is 164 g/mol

The boiling point of water is 100° C.

The boiling point of Eugenol is 254° C.

The density of water is 1.0 g/mL

The density of Eugenol is 1.05 g/mL

By the formula of volume

[tex]\rm V= \dfrac{ [mole\; fraction \times molar\; mass]}{density } \\\\V \;of\; H_2O= \dfrac{ [0.9947 \times 18}{ 1.0 g/mL } = 17.9046[/tex]

The total volume is 30 ml

0.0442 = (volume eugenol/30)

[tex]\dfrac{m\; eug}{m\;H_2O} = \dfrac{p\;eug\times164}{p\;H2O \times18} \\\\\\\dfrac{m\; eug}{30} = \dfrac{4\times 164}{760\times18} \\\\m \;eug = 1.44g[/tex]

Now, calculate the volume

[tex]\rm volume =\dfrac{mass}{density} \\\\volume =\dfrac{1.44}{ 1.05}= 1.37 mL[/tex]

Thus, the volume of eugenol in 30 ml of distillate is 1.37 ml.

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