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The diagram shows two 10 by 14 rectangles which are edge-to-edge and share a common vertex. It also shows the centre O of one rectangle and the midpoint M of one edge of the other.
What is the distance OM?

The diagram shows two 10 by 14 rectangles which are edgetoedge and share a common vertex It also shows the centre O of one rectangle and the midpoint M of one e class=

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Answer:

15

Step-by-step explanation:

Pretend there is a triangle where the hypotenuse is MO

to find the bottom side, we need to find half of 14 (7) and half of 10 (5)

That tells us that the bottom of the triangle is 12.

To find the next side, you will need to use 14 and subtract 10, leaving us with 4. Half of 10 is 5 so 5+4 is 9, so the side facing up is 9.

Now using Pythagorus, the root of 12^2 and 9^2 is 15

Final answer, the distance from O to M is 15

The distance OM is 15 and this can be determined by using the Pythagorean theorem and the given data.

Given :

  • The diagram shows two 10 by 14 rectangles that are edge-to-edge and share a common vertex.
  • It also shows the center O of one rectangle and the midpoint M of one edge of the other.

The following steps can be used in order to determine the distance OM:

Step 1 - Let the OEM be the triangle where the angle OEM is 90 degrees.

Step 2 - The distance OE is given by:

[tex]\rm OE = \dfrac{10}{2}+\dfrac{14}{2} = 12[/tex]

Step 3 - Now, the distance ME is given by:

[tex]\rm ME = 14-10+\dfrac{10}{2} = 5 + 4 = 9[/tex]

Step 4 - Apply Pythagorean theorem on triangle OEM in order to determine the distance OM.

[tex]\rm OM^2 = 12^2+9^2[/tex]

OM = 15

For more information, refer to the link given below:

https://brainly.com/question/11897796

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