As we know that,
Pythagoras triplet
1) a² + b² = c²
Let
[tex]\sf \: {2}^{2} + {2}^{2} = {4}^{2}[/tex]
[tex]\sf \: 4 + 4 = 16[/tex]
2) a² + b² = c²
[tex]\sf \:5 {}^{2} + {12}^{2} = {13}^{2}[/tex]
[tex]\sf \: 25 + 144 = 169[/tex]
3)a² + b² = c²
[tex]\sf {3}^{2} + {5}^{2} = {6}^{2}[/tex]
[tex]\sf 9 + 25 = 36[/tex]
4) a² + b² = c²
[tex]\sf {5}^{2} + {4}^{2} = {7}^{2}[/tex]
[tex]\sf \: 25 + 16 = 49[/tex]
Only B can be Pythagoras triplet.