[tex]\mathbf{Here \ is \ the \ missing \ part \ of \ the \ question} \\ \\ \mathbf{The \ genome \ of \ Escherichia \ coli \ consists \ of \ 4380 \ genes, \ encoding \ 4290} \\ \\ \mathbf{ proteins, \ in \ jus t \ 5175720 \ base \ pairs. \ What \ percent \ fraction \ of\ the} \\ \\ \mathbf{ Escherichia \ coli \ genes \ encode \ proteins?}[/tex]
Answer:
1182
Explanation:
From the information given:
Number of present genes = 4380
the total no. of protein-encoding = 4290
Total no. of base pairs = 5175720
The percentage fraction of genes encoding the protein is;
total no of protein-encoding gene/total no of present genes
[tex]\mathbf{\dfrac{4290}{4380} = 0.9795}[/tex]
= 97.95%
The average number of base pairs per protein-coding gene is;
= total no. of base-pair/ no of present genes
[tex]\mathbf{ \dfrac{5175720}{4380} = 1181.6} \\ \\ \simeq \mathbf{1182}[/tex]
