Respuesta :
Since it states that during each round, half the players would be eliminated, it means that you just have to divide the current number of players by 2. Thus, the rate would be ½ or 0.5 players per round.
The answer is a.0.50
Answer:
a. 0.50
Step-by-step explanation:
Given : The initial number of participants =128
It is given that during each round, half of the players are eliminated.
Then, the number of players after first round = [tex]128-(128\times\frac{1}{2})=128(1-\frac{1}{2})=64[/tex]
Hence, the exponential decay equation for the given situation will be :-
[tex]y=128(1-\frac{1}{2})^n[/tex], gives the number of players after nth round.
On comparing with the standard exponential decay equation [tex]y=A(1-r)^n[/tex], where r is the rate of decay
We get the decay rate = [tex]\frac{1}{2}=0.50[/tex]