Answer: The sampling distribution of the difference in sample proportions is approximately normal
Step-by-step explanation:
Given that :
Random sample of deer from one region = 200
p = 0.06
1 - p = 1 - 0.06 = 0.94
Random sample of deer from other region = 197
p = 8.6% = 0.086
1 - p = 1 - 0.086 = 0.914
For an approximately normal distribution :
np ≥ 10
n(1 - p) ≥ 10
(200) (0.06) = 12
(200) (0.94) = 188
(197)(0.086) = 16.942
(197)(0.914) = 180.058
Since all conditions are met :
Then, the sampling distribution of the difference in sample proportion is approximately normal.