Respuesta :
Answer:
The answer is: Find the slopes of AB and AC. If the product of the slopes is -1, then the sides meet in a right angle.
Step-by-step explanation:
From Analytical Geometry, two lines are perpendicular to each other if and only if [tex]m_{1}\cdot m_{2} = -1[/tex], where [tex]m_{1}[/tex] and [tex]m_{2}[/tex] are the slopes of each line, respectively. According to this, the following expression must be observed:
[tex]m_{AB} \cdot m_{BC} = -1[/tex] (1)
Each slope can be determine by definition of the slope of a Secant Line:
[tex]m_{AB} = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}[/tex] (2)
[tex]m_{BC} = \frac{y_{C}-y_{B}}{x_{C}-x_{B}}[/tex] (3)
Where:
[tex]x_{A}[/tex], [tex]x_{B}[/tex], [tex]x_{C}[/tex] - x-Coordinates of points A, B and C.
[tex]y_{A}[/tex], [tex]y_{B}[/tex], [tex]y_{C}[/tex] - y-Coordinates of points A, B and C.
If we know that [tex]x_{A} = 0[/tex], [tex]y_{A} = 0[/tex], [tex]x_{B} = 50[/tex], [tex]y_{B} = 0[/tex], [tex]x_{C} = 18[/tex] and [tex]y_{C} = 24[/tex], then the relationship between slopes is:
[tex]m_{AB} = \frac{0-0}{50-0}[/tex]
[tex]m_{AB} = 0[/tex]
[tex]m_{BC} = \frac{24-0}{18-50}[/tex]
[tex]m_{BC} = -\frac{3}{4}[/tex]
[tex]m_{AB}\cdot m_{BC} = 0\cdot \left(-\frac{3}{4} \right)[/tex]
[tex]m_{AB}\cdot m_{BC} = 0[/tex]
Which means that both line segments are not perpendicular to each other.
In a nutshell, we need to find the slopes of AB and CB, if the product between both slopes is -1. Then, the sides meet in a right angle.