Given:
The area of the rectangle RSTU = [tex]36x^2+25x-25[/tex]
Length of the rectangle RSTU = [tex]4x+5[/tex]
To find:
The width of the rectangle RSTU.
Step-by-step explanation:
We have,
[tex]36x^2+25x-25[/tex]
Splitting the middle term, we get
[tex]=36x^2+45x-20x-25[/tex]
[tex]=9x(4x+5)-5(4x+5)[/tex]
[tex]=(4x+5)(9x-5)[/tex]
We know that, the area of a rectangle is
[tex]Area=Length \times width[/tex]
Area of rectangle is product of (4x+5) and (9x-5).
Since (4x+5) is the length of the rectangle, therefore, (9x-5) is the width of the rectangle RSTU.
