Answer:
1 mole of platinum (Pt).
Explanation:
From the question given above, the following data were obtained:
Platinum (Pt) = 117.4 g
Carbon (C) = 28.91 g
Nitrogen (N) = 33.71 g
Number of mole of platinum =?
To obtain the number of mole of platinum present in the compound, we shall determine the empirical formula for the compound. The empirical formula for the compound can be obtained as follow:
Pt = 117.4 g
C = 28.91 g
N = 33.71 g
Divide by their molar mass
Pt = 117.4 /195 = 0.602
C = 28.91 /12 = 2.409
N = 33.71 /14 = 2.408
Divide by the smallest
Pt = 0.602 /0.602 = 1
C = 2.409 /0.602 = 4
N = 2.408 / 0.602 = 4
Therefore, the empirical formula for the compound is PtC₄N₄ => Pt(CN)₄
From the empirical formula for the compound (i.e Pt(CN)₄) we can see that the compound contains 1 mole of platinum (Pt).
